Conversation Between Retro.spex and ak137
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Yeah thats the final answer, you're meant to work in Us. If you work in U, you dont need to sub U back in at the end
Sorry I only just saw the second sheet Yes I love the smiley faces
So is the final answer you got 1/4ln3/2 - 1/12??
Feel like I should have calculated the u values as well (I usually leave it till last after I've integrated)... oh well, it's over now!
Oh and did you like the smiley faces at the end =P
Haha yeah. And its alright.
Yeah Ill think you'll get a few marks for it, maybe 2 or 3, depending on how much you got done
No worries, SAME! I seriously think I had the best sleep I've ever had last night haha!
Thanks for that I completely missed the fact you could cancel the x's and tried to change everything to be in U form Oh well! Do you think I'll get any marks for finding du/dx and all that crap?
Thanks again for that!
Hey, sorry, I went to sleep last night (I was that tired!), but ive done the sub question this morning
Ive written notes down the right hand side on what I did in each step Feel free to ask if you're not sure what Ive done
Here, its on two pieces of paper (right click and open the image in new tab and you should be able to zoom in, if you cant see it clearly ):
Okay I did the investigating:
(Integral between 1 and 0) of x^7/(x^4+2)^2dx
u = x^4 + 2
X^7/ X^3 + 2
That was it, wasnt it? Was it plus 2 at the end? And the limits, i cant remember
Hmmmm I'll have to do some investigating and get back to you