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# Conversation Between ColdKant and Joerod

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1. ColdKant
12-06-2012
first you must work out what one litre is equal too since they have given you 200 gallons
therefore if you look on the graph you can work it out to be approx 1g=4.5 litres
since you know the conversion now convert the gallons into litres and you get 908,000cm3
it is easier to convert gallon into litres since the units are cm3 which are the same for the volume they require for the tank, since you have that now you work out the volume of the tank which is pi x 60^2 x 180 and you get 2035752.04cm3 since thats the volume for the FULL tank you divide and get it for half the tank which is 1017876.02 and you use your previously converted 900 gallons and get 908000< 1017876.02 therefore it is more than full, next question just remember the compound coversion of density = mass divided by volume, since you have the volume of 908,000 you next to rearrange the equation to multiply it by the density which is 0.85 and you should get 771800g converted to kg that is 771.8g get it?
2. Joerod
12-06-2012
Can you please explain how 6b of the SAM, Paper 2 can be solved using the second answer of the mark scheme - 224 gallons. The mark scheme shows the working with the first answer - 908000 cm3
3. Joerod
12-06-2012
hi,

do you have the mock paper for the gcse maths 1mao/2h exam tomorrow - can u pls email to gretrod@hotmail.com

thanks and regards
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