Full Ionic Equation? Nitric acid and calcium carbonate

Hey! I'm having some problems with writing the full ionic equation of the reaction between calcium carbonate and nitric acid.

I understand that:

Metal carbonate + acid --> salt + water + carbon dioxide

Thus:

CaCO_3(s) + 2HNO_3(aq) --> Ca(NO₃)_2(aq) + H₂O_(l) + CO_2(g)

So, then putting in the aqueous ions:

CaCO_3(s) + 2H⁺_(aq) + NO₃^2-_(aq) --> Ca²⁺_(aq) + NO₃^2-_(aq) + H₂O_(l) + CO_2(g)

Cancelling the spectator ions:

CaCO_3(s) + 2H⁺_(aq) --> Ca²⁺_(aq) + H₂O_(l) + CO_2(g)

So, is this it? I believe so, given that CaCO_3(s) is a solid, and H₂O_(l) and CO_2(g) are covalently bonded. Am I wrong? The mark scheme to the question that posed this problem says I am! :s-smilie:

Reply 1

EierVonSatan

Its safe to assume that the aqueous acid would dissolve the calcium carbonate :smile:

Reply 2

Dstbgre

That is mainly correct.
However when you put in the aqueous ions you couldnt have NO3 2-, you would have 2NO3 1-.

The rest of the equations are correct.
CaCO3 is a solid, H2O and CO2 are both covelently bonded.

What does the markscheme say is wrong?