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Simple Maths questions.

1. Simplify √24 +√6. I got 5√12...is this correct?

2. Express (fraction) 36 which is over 5-√7 in the form a+b√7, where a and b are integers. I got 10+2√7...is this correct?

3. Make X the subject of this formula: (its a fraction) 'a', over (x-b)^2=c (the whole fraction equals C, not the (x-b)^2)

^^ I cant seem to get a reasonable looking answer for no.3.
Reply 1
Avatar for CJN
CJN
17
1. No, the answer is in terms of √6 only, just simplify the √24 into √6's.

2. Yes it is

3. What answer did you get?
simple?
Reply 3
Avatar for Saif95
Saif95
OP
12
Original post by CJN
1. No, the answer is in terms of √6 only, just simplify the √24 into √6's.

3. What answer did you get?


I got a^2+b (all over) c^2 =x (whole fraction equalling x not the c^2)
Right or not? If not whats the right answer?

And is the answer to Q1. 4√6?

Thanks.
Reply 4
Avatar for Nucleo
Nucleo
√24 + √6 is not 4√6
√24 => √4√6 => 2√6

2√6 + √6, which is 3√6 not 4 :redface:
Reply 5
Avatar for datinggod
datinggod
I got 3√6 for Q1

√24 broken down to √6*√4, so that's 2√6.

2√6 + √6 = 3√6

My maths is a bit rusty so I don't exclude being completely wrong
Reply 6
Avatar for ryan84
ryan84
7
Original post by Saif95
I got a^2+b (all over) c^2 =x (whole fraction equalling x not the c^2)
Right or not? If not whats the right answer?

And is the answer to Q1. 4√6?

Thanks.


What is root 24 in terms of root 6?
Reply 7
Avatar for Saif95
Saif95
OP
12
Original post by Nucleo
√24 + √6 is not 4√6
√24 => √4√6 => 2√6

2√6 + √6, which is 3√6 not 4 :redface:


Original post by ryan84
What is root 24 in terms of root 6?


Yh thanks I get it now...

can you tell me if my answer to the 3rd question was right? if not what is it?
thanks.
Reply 8
Avatar for CJN
CJN
17
Original post by Saif95
Yh thanks I get it now...

can you tell me if my answer to the 3rd question was right? if not what is it?
thanks.


Not sure what you are doing, but:

a(x−b)2=c \dfrac{a}{(x-b)^2} = c


c×(x−b)2=a c \times (x - b)^2 = a


(x−b)2=ac (x - b)^2 = \dfrac{a}{c}


x−b=ac x - b = \sqrt{\dfrac{a}{c}}


x=ac+b x = \sqrt{\dfrac{a}{c}} + b

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