but-2-ene exists as two geometrical isomers, explain why but-2-ene exists as two geometrical isomers. (2 marks) this is a question from january 2008,though......i cuouldn't find a simple way to answer this,can anybody help me please?
because you can have e-z isomerism?
for example
remember there is a c=c double bond, your priority group (CH3) can be either on the same side of the c=c bond or can be on the opposite side .
That's correct. There are 2 other main observations though - a smell of bad eggs (from the H2S gas) and a yellow solid may form.
Next question: Explain why boron trichloride, BCl3, is non-polar despite having polar bonds.
What's the full equation for the reaction between sulphuric acid and potassium iodide then?
For the boron trichloride: All ends of the compound from top to bottom, and left to right are slightly negative. So it only relies on dispersion forces?
Helllooo I'm going through the alcohols topic yeh.. & i came across 2 contracting stuff.. first of all..would the reaction be affected if we use alcoholic ammonia & just excess ammonia..?? According to the AS chem blue text book it says CH3CH2I + NH3 ---> CH3CH2NH2 + HI
Where as in the george facer textbook, When excess ammonia is used, it forms CH3CH2CH2Cl + 2NH3 ---> CH3CH2CH2NH2 + NH4Cl & it even says stating HCl as a product of this reaction is a common error in AS ???
Helllooo I'm going through the alcohols topic yeh.. & i came across 2 contracting stuff.. first of all..would the reaction be affected if we use alcoholic ammonia & just excess ammonia..?? According to the AS chem blue text book it says CH3CH2I + NH3 ---> CH3CH2NH2 + HI
Where as in the george facer textbook, When excess ammonia is used, it forms CH3CH2CH2Cl + 2NH3 ---> CH3CH2CH2NH2 + NH4Cl & it even says stating HCl as a product of this reaction is a common error in AS ???
Which one is correct???
Both are technically correct but the HI in the first one would go onto react with another NH3 molecule to form NH4I. The overall equation would be the second one.
Both are technically correct but the HI in the first one would go onto react with another NH3 molecule to form NH4I. The overall equation would be the second one.
righhht Makes sense ! Basically in the exam we should write the second equation, isnt it ?! Thanksss !
Both are technically correct but the HI in the first one would go onto react with another NH3 molecule to form NH4I. The overall equation would be the second one.
Name all of the intermolecular forces operating in molecules of propanal.
so propanal is an aldehyde, therefore NO HYDROGEN BONDS OCCUR, however PERMANENT DIPOLE DIPOLE interactions OCCUR and of course LONDON FORCES OCCURS IN ALL MOLECULES MOLECULES