Hey all!
I'm stuck on differentiating these questions...
1) ln(sinx) << why can't I just use the product rule on this? Like have u=ln and v=sinx and then differentiate the two to get du/dx = 1/x and dv/dx = cosx therefore giving sinx/x + lncosx? However, in the mark scheme it says...
1/sinx x cosx = cotx... But i don't get where they've got this from?
2)6e^tanx... I really don't know how to approach this at all
MARK SCHEME = 6e^tanx x sec^2x = 6e^(tanx)sec^2x
3) square root of cos2x MARK SCHEME = 1/2(cos2x)^-1/2 x (-2sin2x)
=-(sin2x)/square root of cos2x
If there is any kind person out there who could explain to me how the answer has been derived please, then I would greatly appreciate it