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2012 Higher Physics Discussion

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Anyone know the answer to mc Q6?
Reply 601
Avatar for jahmez95
jahmez95
Original post by KeithyDee
That is not tutor/teacher answers though, just what some people have said.


well here you go then


1E
2A
3C
4C
5C
6D
7B
8D
9B
10C
11B
12E
13D
14E
15D
16A
17A
18D
19B
20B
Original post by aroy45
Can someone explain what I'm doing wrong for 21a


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Your diagrams wrong, the angle should be 70 degrees
Ill put my answers up for people to correct or agree
21a 15.9km at 157 degree
ii) 3.53m/s
B). 15.9km at 157
ii) 2.94m/s

22ai) 61.2m
ii) 11.475m
B). More likely as ball will not travel at far and reach max height earlier

23) proof
ii). 42318m/s
B) 5.6x10^-3
C) xenon as f=ma as mass is bigger acceleration the same. (very unsure)

24). Proof p/Tk is a constant
B). More collisions with each other and outer walls
C). Stopper could be moved by different pressures acting could change volume. (wrong I think)

25) 1.5A
ii) 3v
iii) 13.5W

B) Internal resistance is lower

26) graph with voltage starting at 0 and levelling out at 12V
B) 5kohms (might be 6kohms)
C)the voltage is the same (not sure)
ii). The capacitance in this instance is the same as the voltage does not change (unsure)

27) proof
B) differential
ii) 5.6
B(a) 1.93v
B(b) 55mm (think its 65)

28) 51 degrees
B) partial internal reflection
ii) 48.8 degrees
C). Sketch shows total internal reflection

29a) 3.3x10^-6m
B) 3.03x10^5
C) yes as it falls within the uncertainty range

30) decrease
B) photoconductive
ii). Current increases
C) 6.75x10^-6

31) 0.0125j (wrong?)
B) alpha
Reply 604
Avatar for bob169
bob169
Original post by KeithyDee
The displacement was 15.7 +/- 0.2km.


no, it was 16km and +- 10m cos you have to round of 15.7 to 16 and every answer 2 significant figures cos the question was in 2 sig fig, there was no decimal places.
Reply 605
Avatar for bob169
bob169
Original post by TheZorse94
Ill put my answers up for people to correct or agree
21a 15.9km at 157 degree
ii) 3.53m/s
B). 15.9km at 157
ii) 2.94m/s

22ai) 61.2m
ii) 11.475m
B). More likely as ball will not travel at far and reach max height earlier

23) proof
ii). 42318m/s
B) 5.6x10^-3
C) xenon as f=ma as mass is bigger acceleration the same. (very unsure)

24). Proof p/Tk is a constant
B). More collisions with each other and outer walls
C). Stopper could be moved by different pressures acting could change volume. (wrong I think)

25) 1.5A
ii) 3v
iii) 13.5W

B) Internal resistance is lower

26) graph with voltage starting at 0 and levelling out at 12V
B) 5kohms (might be 6kohms)
C)the voltage is the same (not sure)
ii). The capacitance in this instance is the same as the voltage does not change (unsure)

27) proof
B) differential
ii) 5.6
B(a) 1.93v
B(b) 55mm (think its 65)

28) 51 degrees
B) partial internal reflection
ii) 48.8 degrees
C). Sketch shows total internal reflection

29a) 3.3x10^-6m
B) 3.03x10^5
C) yes as it falls within the uncertainty range

30) decrease
B) photoconductive
ii). Current increases
C) 6.75x10^-6

31) 0.0125j (wrong?)
B) alpha

agree with everything but tehcnically speaking 21) answers had to be in 2 sig figures since question was in 2 sig figures dont think that matters unless you put too many
Original post by DragonHeartstring
Me too-ish! I drew it going west instead of east :rolleyes: Just hope that what I got as displacement and bearing is right for what I drew, then I might still pick up marks.


I also wrote that v=d/t for it, so I'm hoping I maybe pick up a few half marks for formula. And pretty sure I got the time right in the last question, just did everything else wrong!, so annoying as well when you're convinced it's perfect in the exam! :rolleyes:
Original post by S119234
I also wrote that v=d/t for it, so I'm hoping I maybe pick up a few half marks for formula. And pretty sure I got the time right in the last question, just did everything else wrong!, so annoying as well when you're convinced it's perfect in the exam! :rolleyes:


I know! I was hoping for a scale drawing in this exam, and then I go and mess it up! Typical :rolleyes:
I think things are looking fairly good for me, thanks guys :smile:
Reply 609
Avatar for Siwel95
Siwel95
Oh well, now the wait for August begins. I'm still undecided as to open it slowly showing each grade one at a time or just whip it out haha
Original post by Siwel95
Oh well, now the wait for August begins. I'm still undecided as to open it slowly showing each grade one at a time or just whip it out haha


I'm just going to whip it out (my philosophy in life :wink: ) and see how it goes :smile:

Just enjoy the rest of your summer !
Reply 611
Avatar for Siwel95
Siwel95
Original post by KeithyDee
I'm just going to whip it out (my philosophy in life :wink: ) and see how it goes :smile:

Just enjoy the rest of your summer !


haha same goes for you :smile:
Could someone say what the answer to 31(a) is ?, I got 0.00002J using D=E/m, but not particularly sure.

Also, for 28(b)(i), would it not be an acceptable answer to say that it's because the angle in air = 90degrees ?, cause that then leads to the critical angle equation.
Does anyone know what the grade boundary for an A has been the last few years?
Original post by S119234
Could someone say what the answer to 31(a) is ?, I got 0.00002J using D=E/m, but not particularly sure.

Also, for 28(b)(i), would it not be an acceptable answer to say that it's because the angle in air = 90degrees ?, cause that then leads to the critical angle equation.


I got some sort of variation of 0.00002
Reply 615
Avatar for Siwel95
Siwel95
Original post by S119234
Could someone say what the answer to 31(a) is ?, I got 0.00002J using D=E/m, but not particularly sure.

Also, for 28(b)(i), would it not be an acceptable answer to say that it's because the angle in air = 90degrees ?, cause that then leads to the critical angle equation.


yes i got that for 31a) :smile:, as for question 28 i cannot remember the question haha
Original post by Herzschmerz
Does anyone know what the grade boundary for an A has been the last few years?


2011: 64 marks (71%)
2010: 67 marks (74%)
2009: 68 marks (75%)
Original post by Siwel95
yes i got that for 31a) :smile:, as for question 28 i cannot remember the question haha


Thank goodness! :smile:, it was the one asking why the value of theta equals the critical angle for the light in water. Pretty sure that it's because angle in air is 90 degrees.
What has been the grade boundaries for a B over the years?
Reply 619
Avatar for Siwel95
Siwel95
Original post by S119234
Thank goodness! :smile:, it was the one asking why the value of theta equals the critical angle for the light in water. Pretty sure that it's because angle in air is 90 degrees.


ah yes, i wrote that it is refracted at 90 degrees

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