Here is a question which I need help on:
Find the equation of the straight line (in the form ax+by+c=0 where a,b and c are integers) which is the perpendicular bisector the line through (4,9) and (-2,1).
Here are the main parts of my long working out:
I found the midpoint of the line through (4,9) and (-2,1) to be (1,5)
(1,5)=(x
1, y
1)
The gradient of the line through (4,9) and (-2,1) is
68Therefore the gradient of the perpendicular bisector must be
−86y−5=−86(x−1)y−5=−86x+868(y−5)=−6x+6Therefore my answer is the following:
6x+8y−46=0This is incorrect, because the correct answer is 3x+4y-23=0
What have I done wrong???
Thanks a lot for any help provided.