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cos (5pi/12) => exact value
is there a way for me to work out cos (5pi/12) without using the cos-graph but only the "magic triangle" ?
thanks!
thanks!
http://artpad.art.com/?jjfhnudcxw
That's the triangle. Dunno if it's your magic one.
But you're looking to find the lengths cosAcosB and sinAsinB.
[edit]
Well, fine. If you're going to do it the normal way, you might as well just say
5/12 = 1/4+1/6 and cos(A+B) = cosAcosB-sinAsinB.
That's the triangle. Dunno if it's your magic one.
But you're looking to find the lengths cosAcosB and sinAsinB.
[edit]
Well, fine. If you're going to do it the normal way, you might as well just say
5/12 = 1/4+1/6 and cos(A+B) = cosAcosB-sinAsinB.
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