say for example I have to differentiate the function using composite rule (dy/dx=dy/du*du/dx):
y=(2x^2-1)^4
I call the bits in the bracket 'u', and 'y=(x^2-1)^4' becomes y=u^4, then I can differentiate both and apply the chain rule..
then take the function:
y=e^(2x^2-1)
.. Now I have a problem, I have an extra contant (K) of '2' before the x squared.
differenciation of e^kx = ke^kx
What on earth do I call the separate parts of y=e^(2x^2-1)?
I need a 'u' and a 'y', I assume.
Can someone please tell me/work this out with working?
tia.