The Student Room Group
Reply 1
{T1}sin(40) + {T2}sin(60) = 35g

{T1}cos(40) = {T2}cos(60)
Reply 2
DeanK2
{T1}sin(40) + {T2}sin(60) = 35g

{T1}cos(40) = {T2}cos(60)


Hey, i thought of doing it that way
but how come T1cos40 = T2cos60 ??
I know that the sum should be equal to 35g, tried that way but couldnt progress further


EDIT: got it, horizontally should also be equal because in equilibrium, thanks for your help :smile:

EDIT AGAIN : Then also, i still dont get it :frown: would you get 2 relations then solve?
Reply 3
Bump
Reply 4
You can use the sine rule to find T1 and T2

T1sin50=35gsin100 \frac{T1}{sin50} = \frac{35g}{sin100}

T1=35gsin50sin100 T1 = \frac{35gsin50}{sin100}

Then repeat for T2.

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