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\dfrac{3x+1}{\left(x+1\right)^2} = \dfrac{A\left(x+1) + B}{\left(x+1\right)^2} = \dfrac{A}{x+1} + \dfrac{B}{\left(x+1\right)^2}
\dfrac{3x+1}{\left(x+1\right)^2} = \dfrac{A\left(x+1) + B}{\left(x+1\right)^2} = \dfrac{A}{x+1} + \dfrac{B}{\left(x+1\right)^2}
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