Thing is, I forgot about this resit, I had two maths exams last week ( stats T.T ) and biol with another maths exam this week, and I know I haven't done enough revision for it..
so I came across this question in Jan12 paper and I got a completely different answer from the markscheme on what the name of it is... the markscheme says it's called 2,2 dichloro 3 methyl pentane....i don't understand why, anyone wanna help me?
so I came across this question in Jan12 paper and I got a completely different answer from the markscheme on what the name of it is... the markscheme says it's called 2,2 dichloro 3 methyl pentane....i don't understand why, anyone wanna help me?
Longest carbon chain is 5 so PENT No C=C so ANE 2Chlorines on Carbon2 So 2,2 Dichloro 1 Methyl group on Carbon 3 so 3 Methyl Add them together in alphabetical order 2,2-Dichloro-3-MethylPentane
so I came across this question in Jan12 paper and I got a completely different answer from the markscheme on what the name of it is... the markscheme says it's called 2,2 dichloro 3 methyl pentane....i don't understand why, anyone wanna help me?
It's pent- because the longest chain is five carbons (it's not straight it's goes 'round the corner' the CH3 group on the bottom right is carbon number 1 if you get me). The chlorines are both on the second carbon and then there is a methyl group on the third carbon. That's actually quite complicated when you look at it, I definitely wouldn't have got that answer :L
You would deduce which way you look at it gives you the smallest number on the carbon chain, from left to right it would be 4,4-DiChloro-3-MethylPentane. You then would look at it from the other way (right to left) and it would be 2,2-DiChloro-3-MethylPentane. As you can see the position of the functional groups on the 2nd Haloalkane is lower than the 1st Haloalkane so that would be it. Hope this makes sense.