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How do you work out the volume needed to completely react in this example?

If you were told that 2 reactants, e.g. Hydrogen and oxygen, had a molar ratio of 2:1, and hydrogen had a volume of 12dm3, how would you determine the volume of oxygen?
Simple.. You would get a spaceship, blast it into space, watch it orbit the earth a bit, collect some cheese particals from the moon before coming back down to earth. The Volume of oxygen would be 1.33* recurring. etc etc. simples.
Reply 2
Well, you have 2 parts Hydrogen for 1 part Oxygen

So you have 12dm3 Hydrogen for xdm3 Oxygen
Original post by nervouspupil123
If you were told that 2 reactants, e.g. Hydrogen and oxygen, had a molar ratio of 2:1, and hydrogen had a volume of 12dm3, how would you determine the volume of oxygen?


first u have to calculate the moles of hydrogen present from the given volume, them divide it by 2 cz the molar ratio is 2:1, so now u have the amount of oxygen in moles. then determine the volume of oxygen present from the moles of oxygen
Reply 4
Original post by aeyurttaser13
first u have to calculate the moles of hydrogen present from the given volume, them divide it by 2 cz the molar ratio is 2:1, so now u have the amount of oxygen in moles. then determine the volume of oxygen present from the moles of oxygen


Why convert volume to moles to convert back to volume?
Original post by ekudamram
Why convert volume to moles to convert back to volume?


i meant for more complex calculations, right now there is no need. i wrote it as a guideline to further questions so the logic behind it is clear :tongue:
so what is the answer? and what would it be for 10cm3 hydrogen and unknown vol. oxygen, with the same (2:1) ratio?
(edited 11 years ago)
Original post by ekudamram
Well, you have 2 parts Hydrogen for 1 part Oxygen

So you have 12dm3 Hydrogen for xdm3 Oxygen


what is x :L
anyone?
Reply 9
12dm3 of a given volume is hydrogen, and so what, multiplied by 2, gives 12?

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