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f(x)=x squared

given that f(x)=x squared sketch these graphs, each on a seprate diagram, and find an expression, giving Y in terms of X, for each function.

a: y=f(x)-1
b: y=f(x+1)
c: y=f(2x)
d: y=-3f(x)

i no how to draw these graphs out but i do not get what it means by find the expression giving y in terms of x?

can any one please explain this:smile:
Reply 1
Avatar for A.J.B
A.J.B
y=f(x)-1
f(x)=x^2
y=x^2-1
and etc
Reply 2
Avatar for BJack
BJack
19
We know that f(x)=x2f(x)=x^2. Then y=f(x+1)⇒y=(x+1)2y=f(x+1) \Rightarrow y=(x+1)^2 etc.
Reply 3
Avatar for miv
miv
In these relations you just put the x square instead of f(x) and you find the expression of y in terms of x.
sahil112
given that f(x)=x squared sketch these graphs, each on a seprate diagram, and find an expression, giving Y in terms of X, for each function.

a: y=f(x)-1
b: y=f(x+1)
c: y=f(2x)
d: y=-3f(x)

i no how to draw these graphs out but i do not get what it means by find the expression giving y in terms of x?

can any one please explain this:smile:

They want to know the equations of the 4 graphs that you have drawn.
Reply 5
Avatar for sahil112
sahil112
OP
13
Maths Buster
They want to know the equations of the 4 graphs that you have drawn.

havnt they already given it?
sahil112
havnt they already given it?

They want the equations to involve x, not f. And so your 1st equation would be y = x^2; your 2nd equation would be y = [x + 1]^2. And so on.
Reply 7
Avatar for sahil112
sahil112
OP
13
Maths Buster
They want the equations to involve x, not f. And so your 1st equation would be y = x^2; your 2nd equation would be y = [x + 1]^2. And so on.

ah ok thanks for your help:biggrin:

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