The Student Room Group
velocity is the first derivitive of displlacement with respect to time.

... perhaps if you gave the entire question we may be able to help - integrating squares of derivitives is diffcult in most cases.
Reply 2
Its v a known function of t. If so substitute that in.

If you are trying to solve the differential equation

[br]dvdt=kmv2[br][br]\displaystyle \frac{dv}{dt} = \frac{k}{m}v^2[br]

Then you must seperate your variables before integrating
Reply 3
That is what i'm trying to do SCE1912 I think I've done it now.
Is the solution t=mkv+c t = \frac{m}{kv}+c
you need a minus
Reply 5
oh yeah got it now thanks guys

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