May someone please help me with questions 16 and 21
can sort of do 16 by using logic but
45 r = 50 r - 1.5 5r = 50 x 1.5 5r = 75
r = 15
21
force on a moving charge is = Bqv, so I think it's A.
ahh piss, it wants the time, so it wants velocity, so the answer is C because the force is the same for both (same charge) but f = mv^2 / r says the velocity will be slower for the bigger mass, so the time period is bigger
the electron is travelling clockwise, the force must always act to the centre, and the middle finger must be in the opposite direction to the direction of the electron, so you can work it out using the LHR
you won't need to know that, i'm not sure if I even know that but I wouldn't be worried
mind giving me the basics anyway ?
The main purpose of banking the track is to reduce friction on the tyres from centripetal forces. When you bank the track the contact force can contribute to the centripetal force.
So if we say contact force is N, and its banked (theta) from the horizontal, then Ncos(theta) + Frictional forces = mv^2.
If it wasnt banked then the frictional forces would have to be greater, hence worn tyres (for example). I think it helps you go round bends faster not sure though.
Can someone explain how a mass spectrometer works please?
It says that the beams enter at the same velocity beause they go through the 'velocity selector' - wth is this?
Are they even on the spec? My teacher never mentioned them. This is an absolute shot in the dark here but maybe the velocity selector is a uniform magnetic field perpendicular to the velocity of the beams? Then because F=BQv the faster travelling beams will be deflected further and won't enter the spectrometer?
Are they even on the spec? My teacher never mentioned them. This is an absolute shot in the dark here but maybe the velocity selector is a uniform magnetic field perpendicular to the velocity of the beams? Then because F=BQv the faster travelling beams will be deflected further and won't enter the spectrometer?
its in one of the 'how science work' textbox in the book, if you just have a look at it, its on somewhere in chapter 7 I think
Mass spectrometer is definitely not in the physics course
how do you know for sure?
I mean, they have it on the official textbook, why did they bother having such a detailed page on it , argh wasted about 30mins on trying to understand it.
they can ask you questions on it that dont require u to know how it works so u dont need to learn anything about it, its on the as chemistry sylabus though
Can someone explain how a mass spectrometer works please?
It says that the beams enter at the same velocity beause they go through the 'velocity selector' - wth is this?
ions are accelerated to a uniform speed using an electric field to ensure that differences in deflection are due to differences in mass rather than momentum
ions are accelerated to a uniform speed using an electric field to ensure that differences in deflection are due to differences in mass rather than momentum
I thought it says somewhere in the textbook that electric fields don't change the velocity of the particle or something along the lines of this:
''no work is done by the magnetic field on the particle as the force always acts at right angles to the velocity of the particle . Its direction of motion is changed by the force but not the its speed. The kinetic energy of the particle is unchanged by the magnetic field''
On page 127 of the nelson thornes textbook, why is it that in figure 3, it shows the coil parallel with the field lines with emf at a maximum?
is it just me, or is it contradictory, just on the same page, they mention that ''the induced emf is zero when the sides of the coil move parallel to the field lines''
On page 127 of the nelson thornes textbook, why is it that in figure 3, it shows the coil parallel with the field lines with emf at a maximum?
is it just me, or is it contradictory, just on the same page, they mention that ''the induced emf is zero when the sides of the coil move parallel to the field lines''
that threw me off too, but know that the emf is at a maximum when the coil is cutting MOST of the field, as emf = deltaBAN/t , so when the face of the coil is parallel to the field. i.e the change in area or b field usually, as its' difficult to quickly wrap wires on to coils quickly!
i think that sentence meant instead of the coil turning clockwise/anticlockwise perpendicular to the field, it would be turning anticlockwise/clockwise in the same plane, so there would be no change in area cut even though the the area cut is a maximum. a little bit confusing and should really have a diagram considering it's not the easiest topic at all (my worst topic infact)