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differentiate y = sin^(-1)x
i tried using chain rule, with u = sin x
I get -cosx/sin x
but answer is
1/(1-x²)^1/2
I get -cosx/sin x
but answer is
1/(1-x²)^1/2
y=sin-1x
sin y = x
cos y = dx/dy
dy/dx=1/cos y
and....
sin y=x
sin^2y=x^2
1-cos^2y=x^2
(1-x^2)^1/2= cos y sub that into 1/cos y
sin y = x
cos y = dx/dy
dy/dx=1/cos y
and....
sin y=x
sin^2y=x^2
1-cos^2y=x^2
(1-x^2)^1/2= cos y sub that into 1/cos y
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