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Reply 1
when you have a function, y=x^2 or something like that, you diffrentiate the function and make dy/dx=0, thats to find the stationary points, if you then diffrentiate again(this example is not useful for this bit) and you sub in your values obtained from dy/dx=0 then if the outcome number is above 0 then it is a minimum, if it is below 0 then it is a maximum. Look in the spoiler for my example

Spoiler

EDIT: sorry its a bit messy, I tried to avoid latex because its hard to use and annoying at times :smile:
(edited 13 years ago)
Reply 3
Original post by Eloades11
when you have a function, y=x^2 or something like that, you diffrentiate the function and make dy/dx=0, thats to find the stationary points, if you then diffrentiate again(this example is not useful for this bit) and you sub in your values obtained from dy/dx=0 then if the outcome number is above 0 then it is a minimum, if it is below 0 then it is a maximum. Look in the spoiler for my example

Spoiler

EDIT: sorry its a bit messy, I tried to avoid latex because its hard to use and annoying at times :smile:


What happens when you second differentiate for example: -6x+2
you get -6
you cannot sub any of the values obtained from first differentiation. what to do then?

thanks!
Reply 4
Original post by dream123
What happens when you second differentiate for example: -6x+2
you get -6
you cannot sub any of the values obtained from first differentiation. what to do then?

thanks!


y=-6x + 2
dy/dx = -6
when dy/dx=0
-6=0?
no stationary points, as you should already know if you just sketch the graph of -6x + 2
(cant find maximum and minimum points if theres no stationary pionts!)
hope this helped
Reply 5
Original post by jayseanfan
How do find the minimum/maximum point on a curve? and can you give an example please

By the way keep this to Core 1 level/AS level

Exam board is edexcel.

Im a bit confused because the book doesn't mention anything about them, but sometimes I need to calculate them.

Thanks


Use of differentiation to solve problems with Max/Min points is part of C2 not C1 for Edexcel

You might be expected to use completed square to find the minimum point of a quadratic but that's all. [ the min of (x + p)^2 + q occurs at (-p,q) ]

e.g. x^2 + 6x + 5
= (x + 3)^2 - 4
minimum is at (-3, -4)

If you are asked to sketch a graph of a given function you will be required to show where it crosses the axes
If you are asked to sketch a transformation of a graph you are reuired to label the new coordinates of points labelled on the original graph
(edited 13 years ago)
Reply 6
Original post by gdunne42
Use of differentiation to solve problems with Max/Min points is part of C2 not C1 for Edexcel


If I knew this I would have pointed it out, but im on OCR doing A2 at the moment, similar topics though right? Plus people assumably doing C1 will do C2, but it would take a bit of pressure off if you learnt them in order. I ended up revising C4 for my C3 mock :/
Reply 7
Original post by jayseanfan
How do find the minimum/maximum point on a curve? and can you give an example please

By the way keep this to Core 1 level/AS level

Exam board is edexcel.

Im a bit confused because the book doesn't mention anything about them, but sometimes I need to calculate them.

Thanks


Wait, I'm doing Edexcel Maths, C1 and I've never been asked to calculate this. There's nothing in the book about it either. Can someone just confirm whether or not this could be in the exam, because I'm confused now, and we haven't been taught this :confused:
Reply 8
Nope thats C2. :smile:
Reply 9
Original post by Eloades11
If I knew this I would have pointed it out, but im on OCR doing A2 at the moment, similar topics though right? Plus people assumably doing C1 will do C2, but it would take a bit of pressure off if you learnt them in order. I ended up revising C4 for my C3 mock :/


Yep pretty much the same topics on the different awarding bodies but differences in which are in C1 and which in C2. Finding turning points/stationary points by setting dy/dx = 0 is C2 for Edexcel. Finding d^2y/dx^2 of a function is in Edexcel C1 and has occassionally been asked in the exam but you don't learn to do anything with it in terms of max/min points until C2. They will eventually cover it but don't need to know it for their January C1 exam.

Specification: http://www.edexcel.com/migrationdocuments/GCE%20New%20GCE/UA024850%20GCE%20in%20Mathematics%20issue%202%20180510.pdf
e.g.

y = x^2 + 6x, find the coordinates of the minimum point

start by differentiating (dy/dx will give you the formula for the gradient)

dy/dx = 2x + 6

minimum point => dy/dx = 0 (remember, at minimum/maximum points the gradient is 0 since at this particular instant the graph isn't increasing or decreasing)

therefore 2x + 6 = 0
2x = 6
x = 3

sub x = 3 into y = x^2 + 6x to get y = 27

the coordinates of your minimum point are therefore (3,27)

(main point: dy/dx will give you the formula for the gradient)
(edited 13 years ago)
now what if you where given a function like this y=x^3/x^2-1 and told to find max and min points of that curve?
Reply 12
Original post by shady2.0
now what if you where given a function like this y=x^3/x^2-1 and told to find max and min points of that curve?


Mate, this is a 5 year old thread...
Original post by Zacken
Mate, this is a 5 year old thread...
yeah I understand mate am just new here
Original post by shady2.0
now what if you where given a function like this y=x^3/x^2-1 and told to find max and min points of that curve?


I assume you meant y=x3x21 y=\frac{x^3}{x^2 - 1} ?
(edited 8 years ago)
Original post by Zacken
Mate, this is a 5 year old thread...
so u gat the answers?
Original post by wmwaimeng
Did you mean y=x3x21 y=\frac{x^3}{x^2 - 1} or y=x3x21 y=\frac{x^3}{x^2} - 1 ?
the first one
Original post by shady2.0
the first one
u gat some answers for that?
Original post by shady2.0
the first one


Using the quotient rule, differentiate the equation and obtain dy/dx then equate it to 0, solve this equation.

Spoiler

(edited 8 years ago)
Original post by wmwaimeng
Using the quotient rule, differentiate the equation and obtain dy/dx then equate it to 0, solve this equation.

Spoiler

ohkay thank you buddy ..you are a life saver