question 1: plot it in the A quadrant. 3x=120, then x=40. unless you want to plot 3x?
and um CAST being positive or negative has nothing to do with the sign right in front of the degree. it has to do with the sign of the value after you put that degree in a trig function. just like in your question, 120 is positive, but if you find the value of cos 120, its -0.5.
and mind you, 240 is also a solution here 3x=240, x=80.
If you need to leave your answer in general form (i.e. include every possible answer), it would be 60 +- 20 + 360n, where n is an integer. But i don't think you would have to do that in a question where you have to plot it.
You wouldn't plot it as 3x, you say Let 3x=X and then work out the solutions and then once you have the solutions say, oh but since 3x=X times the solutions by three.
question 1: plot it in the A quadrant. 3x=120, then x=40. unless you want to plot 3x?
and um CAST being positive or negative has nothing to do with the sign right in front of the degree. it has to do with the sign of the value after you put that degree in a trig function. just like in your question, 120 is positive, but if you find the value of cos 120, its -0.5.
and mind you, 240 is also a solution here 3x=240, x=80.
Okay let's say if you were to plot x=40. This would go into the 'C' quadrant but as TenOfThem said it is negative so you can't plot x=40 in the 'C' quadrant as cos can only be positive there. What now?
Okay let's say if you were to plot x=40. This would go into the 'C' quadrant, then you would draw a line connecting it into the 'A' quadrant. What now?
and you can add 360 as many times as you need to for each of these
Then, divide by 3 to get x
Yes, but you didn't read my question. What would you do first to find the second value after you have gotten the P.V which is 120. (Refer to picture in my previous post)
Yes, but you didn't read my question. What would you do first to find the second value after you have gotten the P.V which is 120.
We got one value as 120deg.
To find the other values, do 360-120 and 360+120, this gives 240 and 480. I don't know your interval, but 480 might be outside the interval, hence our solutions will be, 120 and 240.
Yes, but you didn't read my question. What would you do first to find the second value after you have gotten the P.V which is 120. (Refer to picture in my previous post)
If you do not understand CAST, and you clearly do not, I suggest that you use a different method
You have a red line that represents 120 and you are saying that it is 180-120 ... why
Surely you can see that your 2 red lines (which are correctly positioned) are -48.59 and -131.51
Or that (if you want to go positive) the lines are 228.59 and 311.41
My mistake for writing x = 48.59 (in a rush). So basically it doesn't matter which quadrant the line is in the (360 - theta), (180 - theta), and (180 + theta) is irrelevant?