Hi all,
Hope you are well.
Well I am having a little problem with Hyperbolic Functions....
How exactly would you work the following equation out....?
f 1/3x+5 dx
Just to let you know I know that f means function and other terms in the equation, however I am unsure how you would 'evaluate the above equation.
Would you need to separate the equation into something like....
1) sinh x =
2) cosh x =
3) tanh x =
sech x =???
If so how would I do this.
I imagine the derivatives of these equations below are...
d/dx (cosh x) = sinh x
d/dx (sinh x) = coshx
Correct =/?
However even if they are I do know how to use these analogue trig functions within the hyperbolic function above =/, I am stuck....
Hope you can help + appreciate your time.