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Rate of change of circle inside a square (difficult)

Hi guys, I came across this question and just need a little push I think..

If we have a circle inside a square so that the sides of the square lie tangent to the circle, find the rate of change of the perimeter of the square if the rate of change of the circumference of the circle is 6ms^-1.

I've tried to write the circumference as 2pi*r

so d/dt (2pi*r) = 6 which obviously isn't right, maybe i'm just not thinking straight..any ideas??

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Reply 1
Original post by Extricated
Hi guys, I came across this question and just need a little push I think..

If we have a circle inside a square so that the sides of the square lie tangent to the circle, find the rate of change of the perimeter of the square if the rate of change of the circumference of the circle is 6ms^-1.

I've tried to write the circumference as 2pi*r

so d/dt (2pi*r) = 6 which obviously isn't right, maybe i'm just not thinking straight..any ideas??


SO the rate of r
d/dt(r)=6/(2pi)
The perimeter of the square is 4r
Reply 2
You know it helps to state what topic it is.

You should use connected rates of change.

Label the length of the sides of the square x and the rest should be pretty obvious.

ztibor you didn't do anything lol.

So you have the circumference of the circle

6ms^-1 = dC/dt (C= circumference)

Therefore dP/dt = dP/dC *dC/dt
P = Perimeter of square.
(edited 11 years ago)
Original post by JonathanM
You know it helps to state what topic it is.

You should use connected rates of change.

Label the length of the sides of the square x and the rest should be pretty obvious.

ztibor you didn't do anything lol.


Ztibor has essentially solved the problem so I don't know what you're talking about.

(Except he should've wrote that the perimeter of the square is 8r, I believe).
Reply 4
Original post by hassi94
Ztibor has essentially solved the problem so I don't know what you're talking about.

(Except he should've wrote that the perimeter of the square is 8r, I believe).


How has he solved it? I can't see how he got from "d/dt(r)=6/(2pi)
to "The perimeter of the square is 4r".
Original post by JonathanM
How has he solved it? I can't see how he got from "d/dt(r)=6/(2pi)
to "The perimeter of the square is 4r".


He didn't get from one to the other. He got to the first bit, then gave the second bit of information (which okay was wrong but it's easy to make mistakes) and then left the OP to do the simple last bit.
(edited 11 years ago)
Reply 6
Original post by hassi94
He didn't get from one to the other. He got to the first bit, then gave the second bit of information (which okay was wrong but it's easy to make mistakes) and then left the OP to do the simple last bit.


I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit. Top tip for him, a length of a side of a square isn't the radius.

dC/dt = 6

Perimeter = 4x
Circumference = root(2)*pi*x
P = 4(C/pi*root(2))
dP/dC = 4/(pi*root(2))

dP/dt = 24/pi*root(2)
(edited 11 years ago)
Original post by JonathanM
I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit.


Wow I don't think you're getting this. It has absolute relevance.

If d/dt (2pi r) = 6 then d/dt (r) = 6/2pi = 3/pi

And you can logically work out that the square must be of side 2r and so the perimeter is 8r.

Then we can write d/dt(8r) = 24/pi

Now if there's something wrong there, tell me. Otherwise stop commenting that something is wrong or irrelevant just because you don't understand how it's relevant.
Original post by JonathanM
I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit. Top tip for him, a length of a side of a square isn't the radius.

dC/dt = 6

Perimeter = 4x
Circumference = root(2)*pi*x
P = 4(C/pi*root(2))
dP/dC = 4/(pi*root(2))

dP/dt = 24/pi*root(2)


Where in the world has root(2) come from?
Reply 9
You're answer is wrong the r for the circle is not the same as the r (length of a side) for a square.

Using chain rule I got dP/dt = 24/pi*root(2)
Reply 10
Original post by hassi94
Where in the world has root(2) come from?



Original post by ztibor
SO the rate of r
d/dt(r)=6/(2pi)
The perimeter of the square is 4r


Thanks guys :smile:




Original post by JonathanM
I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit. Top tip for him, a length of a side of a square isn't the radius.

dC/dt = 6

Perimeter = 4x
Circumference = root(2)*pi*x
P = 4(C/pi*root(2))
dP/dC = 4/(pi*root(2))

dP/dt = 24/pi*root(2)



lol, it's actually ironic that the only bit that ztibor got wrong (i.e the 4r bit) is what you're claiming is the only bit he's got right :tongue:
(edited 11 years ago)
Reply 11
Original post by JonathanM
You're answer is wrong the r for the circle is not the same as the r (length of a side) for a square.


Yeah it isn't r. Its 2r. In words, the length of a side of a square is 2 times the radius of the circle within the square.
Reply 12
Original post by Extricated


lol, it's actually ironic that the only bit that ztibor got wrong (i.e the 4r bit) is what you're claiming is the only bit he's got right :tongue:


Well by that I meant if he meant r as a length of the side of the square, not the radius of the circle.
Original post by JonathanM
Top tip for him, a length of a side of a square isn't the radius.

dC/dt = 6

Perimeter = 4x
Circumference = root(2)*pi*x
P = 4(C/pi*root(2))
dP/dC = 4/(pi*root(2))

dP/dt = 24/pi*root(2)


I think you need more help than the OP.
Original post by JonathanM
Well by that I meant if he meant r as a length of the side of the square, not the radius of the circle.


LOL:confused:
Original post by JonathanM
You're answer is wrong the r for the circle is not the same as the r (length of a side) for a square.

Using chain rule I got dP/dt = 24/pi*root(2)


Look if you've set the perimeter to = 4x then each side = x.


Each side is the diameter of the circle and since circumference = pi*diameter then C = pi*x with no root(2)
Reply 16
Original post by F1Addict
Yeah it isn't r. Its 2r. In words, the length of a side of a square is 2 times the radius of the circle within the square.



Urm what?
a76b64967e6a404185e953b.png
Original post by JonathanM
Well by that I meant if he meant r as a length of the side of the square, not the radius of the circle.


"I've tried to write the circumference as 2pi*r"


:lolwut:
Reply 18
Original post by Ilyas
...


I have uploaded the file you requested, here is the link to it.

Sorry for posting it here, but i saw that you had blocked visitor messages.
Original post by JonathanM
Urm what?
a76b64967e6a404185e953b.png


Okay yeah you've understood this completely incorrectly.

Original Post:

"we have a circle inside a square so that the sides of the square lie tangent to the circle"

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