You have to find the area for each bar and add them together, the total area is equal to 70. So you have to double the area of each bar to make it equal to 140. Therefore, the answer is 12.
You have to find the area for each bar and add them together, the total area is equal to 70. So you have to double the area of each bar to make it equal to 140. Therefore, the answer is 12.
but why did you have to double the 70 to make it equal the total frequency? i saw in other histograms, the total area was equal to the total frequency.
You have to find the area for each bar and add them together, the total area is equal to 70. So you have to double the area of each bar to make it equal to 140. Therefore, the answer is 12.
can you not find the area from 90.5-78.5 and times by 0.5 = 6 then cant you do 140/6?
Im not very good at explaining stuff but ill give it a stab
Basically, their are 140 runners, This doesnt mean the area is 140.... The area is W x F.... So the answer for area would be calculated by adding all the W x F together
Im not very good at explaining stuff but ill give it a stab
Basically, their are 140 runners, This doesnt mean the area is 140.... The area is W x F.... So the answer for area would be calculated by adding all the W x F together
Because it isn't always the same as the frequency because it is frequency density, it is a representation of the frequency. Namely, half of it in this case.
In a histogram the area is proportional to the frequency. Area = K x Frequency. So if the Area is 70 and there are 140 runners k is 1/2.
You then use this when it asks to work out the frequency from the area for individual bars etc. The reason you found the area and frequency was the same question was because k was 1 so you were just kinda lucky
Because it isn't always the same as the frequency because it is frequency density, it is a representation of the frequency. Namely, half of it in this case.
In a histogram the area is proportional to the frequency. Area = K x Frequency. So if the Area is 70 and there are 140 runners k is 1/2.
You then use this when it asks to work out the frequency from the area for individual bars etc. The reason you found the area and frequency was the same question was because k was 1 so you were just kinda lucky
In a histogram the area is proportional to the frequency. Area = K x Frequency. So if the Area is 70 and there are 140 runners k is 1/2.
You then use this when it asks to work out the frequency from the area for individual bars etc. The reason you found the area and frequency was the same question was because k was 1 so you were just kinda lucky
so what do we do with the 140 ? do you mean to find the frequency but is the start pint 59.5?