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Is there such a thing a literaly integrating ln x?

Hi there

Is there such a thing a literaly integrating ln x?
Reply 1
Avatar for JeremyB
JeremyB
Yes, it is xln⁡x−xx\ln x - x.

You can find it using integration by parts.
Reply 2
Avatar for Hasufel
Hasufel
16
Yup. choose, as JB says, parts, using Ln(x) = Ln(x) x (1) - derive the Log part, integrate 1 for the other
How do you figuratively integrate a function? :confused:
Reply 4
Avatar for bahjat93
bahjat93
19
Original post by jackie11
Hi there

Is there such a thing a literaly integrating ln x?


I'm gonna take a guess and say you've got a C3 exam 2morrow.
You should avoid integrating Ln X, that's why in integration by parts you make u=Ln x no matter what that way you only have to differentiate it and not integrate it.
This method works because i tried it with a question and came out with the right answer.
Reply 5
Avatar for raheem94
raheem94
13
Here is an example from my book:

Reply 6
Avatar for Hasufel
Hasufel
16
Original post by EEngWillow
How do you figuratively integrate a function? :confused:


Eh?

NO!
(edited 11 years ago)
Reply 7
Avatar for levantine
levantine
12
Original post by Hasufel
Eh?

NO!


well your question said "literally" and dont really know what you mean by using that word in this context?
Reply 8
Avatar for JonathanM
JonathanM
2
xln(x) - x + c
Reply 9
Avatar for qgujxj39
qgujxj39
17
It could be a misspelling of "illiterately".
Reply 10
Avatar for qgujxj39
qgujxj39
17
On a more serious note - the posters who gave the answer are correct, but you should try it yourself. Integrate by parts, using the trick u=ln⁡x,dvdx=1u = \ln x, \frac{dv}{dx} = 1. It may seem weird, but it works.

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