[dream123]

hello,

i am really stuck, well i know what I need to do but not sure hot to go about it.
basically, I am working on vectors and have:

(i + 3j - 6k) and (2i -3j +6k ) and I need to find the gradient...but how do I do this with three co ordinates....
my question: what does the gradient equation become (rather than y2-y1/x2-x1)?

thank yooooou

[Mr. Orange]

x take away x = your rep power

[Chewwy]

(Original post by dream123)
hello,

i am really stuck, well i know what I need to do but not sure hot to go about it.
basically, I am working on vectors and have:

(i + 3j - 6k) and (2i -3j +6k ) and I need to find the gradient...but how do I do this with three co ordinates....
my question: what does the gradient equation become (rather than y2-y1/x2-x1)?

thank yooooou

are you sure this is what you're asked to do?

if so, the points lie on the line r = (1,3m-6) + t(-1,6,-12) (taking one vector from the other to get the direction vector). differentiating wrt t, we get a 'gradient' of (-1,6,-12).

[dream123]

(Original post by Chewwy)
are you sure this is what you're asked to do?

if so, the points lie on the line r = (1,3m-6) + t(-1,6,-12) (taking one vector from the other to get the direction vector). differentiating wrt t, we get a 'gradient' of (-1,6,-12).

well, to be honest I was tring to compare the question I had to y=mx+c because it asked for the equation to the line...but because its vectors...there is another way to go about getting the equation. I just didnt think as much as I should have really before answering the question.
But, thank you for your help. rep on its way...soon.