[davidsmith]

If f(x) = 3+((2^n)/3) and g(x)=3+((3^n)/2) what can we say about both functions.

a) f(x)=o(g(x))

b) g(x)=o(f(x))

c) f(x) is asymptotic to g(x)

d) none of the preceding

o=little o

little o means that the limit as x goes towards c f(x)/g(x)=0

[Coursework.info]

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[Simba]

Well, which do you think are true, and why? What thoughts have you had so far?

[davidsmith]

Originally Posted by Simba

Well, which do you think are true, and why? What thoughts have you had so far?

well i think that the right answer is:

f(x)=og(x)

as the limit goes towards infinity g(x) increases at a faster rate than f(x) therefore f(x)/g(x) =0

the problem is that if I do the limit towards negative infinity then they are asimptotic.

Since the limit is not chosen in teh question which is the right answer?

[DFranklin]

I would assume (and it is an assumption) that you were supposed to consider n->infinity.

(use of 'n' rather than x rather strongly implies they expected the infinity limit).

Note that people also use big-O, little-O notation for as well (and sometimes for tending to 0 from above etc), so there are actually a few potential interpretations. Not specifying which limit to take is bad question setting, to be honest.