Probability density function of poission process

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  1. mcp2's Avatar
    • Exalted and Worshipped Member
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    Probability density function of poission process
    Question 7 in the image, I don't know where to start

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  2. Zhen Lin's Avatar
    • Vengeful, Imperial Overlord of The Student Room
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    Re: Probability density function of poission process
    It's asking you to show that the time between events in a Poisson process is an exponential r.v. Have you never seen this before? Use the hint to get the complementary c.d.f. of T, subtract that from 1 to get the c.d.f., and differentiate to get the p.d.f.
  3. mcp2's Avatar
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    Re: Probability density function of poission process
    Still don't understand :/ I'm trying to use the normal Poisson forumla with ut as the mean so it comes out as (e^-ut)(ut/t!)
  4. Zhen Lin's Avatar
    • Vengeful, Imperial Overlord of The Student Room
    • Posts: 4,791
    Re: Probability density function of poission process
    I don't know how you could be getting t! from anywhere. t is a real number — do you know what, say, \frac{1}{2} ! is? Try again — in the time period [0, t], what is the probability of 0 events?
  5. mcp2's Avatar
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    Re: Probability density function of poission process
    Would it be 0?
  6. Zhen Lin's Avatar
    • Vengeful, Imperial Overlord of The Student Room
    • Posts: 4,791
    Re: Probability density function of poission process
    No...? The number of events in the interval [0, t] is a Poisson r.v. with mean \mu t, like the question says. So what's the probability of 0 events?
  7. mcp2's Avatar
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    Re: Probability density function of poission process
    1/e^ut ?
  8. mcp2's Avatar
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    Re: Probability density function of poission process
    It clicked and it makes sense now, all cool.
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