Arsey you know where you had that the two equation which said it cannot intersect or something like that, but in your solution you used the discriminant but all i said was that 2x2..... cannot be factorise. How many marks do you think i lost?
Thats exactly what I did ! I made them equal each other and commented that they can 't be factorised ? im sure we did not lose all the marks.
guys the grade boundaries you are predicting are way too low. 58/75 for an A personally
Personally I felt it was an easy paper for me as i like the graph elements. However, others hate graphs and hate the excessive manipulation of algebra. So A will be below 58.
Thats exactly what I did ! I made them equal each other and commented that they can 't be factorised ? im sure we did not lose all the marks.
You would lose 1 if not 2 marks. The reason being is you had to use the discriminate of the equation to proove it doesn't factorise. This was a proof question. They had already told you they do not intersect. So you had to show full working. Therefore had to show the combined equation couldn't factorise.
Personally I felt it was an easy paper for me as i like the graph elements. However, others hate graphs and hate the excessive manipulation of algebra. So A will be below 58.
i found it easy, but thats cuz i was a resit. anyway enough of c1 talk, gonna move on to c3
Thats exactly what I did ! I made them equal each other and commented that they can 't be factorised ? im sure we did not lose all the marks.
You had to put them equal to each other, and move everything to one side so you had a quadratic. You could then just say that b^2<4ac, or that the discriminant is negative. (In the quadratic formula b2-4ac is under the square root sign, so it would be a negative number under the square root sign if 4ac is larger than b^2 - no real solutions)
Those who are saying it didn't factorise are right, but you might have had to say why.
Personally I found it fine as it was far easier than further maths, as well as the OCR additional maths fsmq that I did last year, but do think it was trickier than most of the past papers I've done. Some people I was talking to afterwards barely answered the sequences question or that last coordinate geometry one
You would lose 1 if not 2 marks. The reason being is you had to use the discriminate of the equation to proove it doesn't factorise. This was a proof question. They had already told you they do not intersect. So you had to show full working. Therefore had to show the combined equation couldn't factorise.
i showed both the quadratic way and the factorsing way and said the bit about the discriment
yhh it should be low cos the cleverst girl in our centre found it really hard and she has lyk 10A* and like gets near 100% on all her test lol
Personally this paper shouldn't have been hard. Its just edexcel do not make enough exams like this so people assume c1 is going to be easy and requiring no though.
You would lose 1 if not 2 marks. The reason being is you had to use the discriminate of the equation to proove it doesn't factorise. This was a proof question. They had already told you they do not intersect. So you had to show full working. Therefore had to show the combined equation couldn't factorise.
i solved it using quadratic forumula then stated that the line do not intersect ?
Ummm... I did the quadratic part of it, but forgot to do the discriminant and just said that since it had no real solutions they wont intersect is that alright?
You had to put them equal to each other, and move everything to one side so you had a quadratic. You could then just say that b^2<4ac, or that the discriminant is negative. (In the quadratic formula b2-4ac is under the square root sign, so it would be a negative number under the square root sign if 4ac is larger than b^2 - no real solutions)
I had the same method, I completed the square, and you got square root -7 which doesnt exist, therefore the x-coordinates and y-cordinates wont be the same.
the lines did not intersect because there were no real solutions, after doing the the discriminant or quadratic equation there was a root of a minus number i think i got something around square-root of -7, not completely sure though.