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solve sec(x) = - 5

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    Hi,

    To solve sec (x) = (-) 5 you would have to look at it as 1/cos (x) = -5 then doing cos (x) = - 0.2 but I'm not sure what you do from here to find all the values between the interval 0<x>2(pi) in radians

    Anyone help please?

    Thanks
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    cos (2pi - x) = cos x
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    (Original post by Macromolecular)
    Hi,

    To solve sec (x) = (-) 5 you would have to look at it as 1/cos (x) = -5 then doing cos (x) = - 0.2 but I'm not sure what you do from here to find all the values between the interval 0<x>2(pi) in radians

    Anyone help please?

    Thanks
     cosx = -0.2 \implies x = cos^{-1} (-0.2) = \ldots

    Now using the method(i.e. cast/graphs/general solutions) you prefer, find the other solutions in the given range.

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