[Sora]

I am trying to teach myself some of the C3 syllabus for when I go back to start year 13 on the 18th June but I got stuck on this question.

Make P the subject of:



Thanks,
Sora

[TenOfThem]

ln is the opposite of e^

[raheem94]

(Original post by Sora)
I am trying to teach myself some of the C3 syllabus for when I go back to start year 13 on the 18th June but I got stuck on this question.

Make P the subject of:



Thanks,
Sora

Remember,

[Hasufel]

exponentiate both sides, so you get: Exp[LnP] = Exp[-.02t] becomes:

P = Exp[-.02t], since the exponential of a log of something is that something (because the function of an inverse of x is just x)

[Sora]

My book gives the answer:
P = 25e^(-0.02t)

I did what was suggested above and got the answer you gave, but then I went to check and saw this.

[raheem94]

(Original post by Sora)
My book gives the answer:
P = 25e^(-0.02t)

I did what was suggested above and got the answer you gave, but then I went to check and saw this.

The book is wrong. The correct answer has been given by TenOfThem.

[Sora]

(Original post by raheem94)
The book is wrong. The correct answer has been given by TenOfThem.

Thank you