There is way too many rules it's all driving me nuts
How would you factorise this
4n2+8n+3
ok so you can do this in 2/3 ways: 1.The ac method 2.The complete the square method if completely desperate (google) 3.USE quadratic formula when nothing else work EDIT:Always try AC method if this is confusing try complete the square and if both cant seem to work or too complicated to factorise (large numbers); use formula remember your question is given in for ax2+bx+c (when there is x) now step one ac observe 4n2+8n+3 1.axc= 4x3=12 (decide 2 numbers that times together to give 12 and add to give 8) so lets start 1x12 gives you 12 but dont add to give 8. lets try another 6x2 is 12 and add to give 8 2. you have your two numbers so write it in this form and factorise it in a way you get two equal set of bracket (you will see what i mean) 4n2+2n+6n+3 factorise
2n(2n+1) 3 (2n+1) notice how i made it to get 2 common bracket now all you need is (2n+3) (2n+1)
ok so you can do this in 2/3 ways: 1.The ac method 2.The complete the square method if completely desperate (google) 3.USE quadratic formula when nothing else work
At the early stage you only use the other methods to teach you basic algebraic manipulation.
The quadratic formula instantly gives you the roots of the equation and is hence a better method. I can use it five or six times in a row just to sort out far more complex equations. Its good practice for when you need it at the higher levels.