[letr]

7. The reaction to produce a drug has a ΔH value of –10.07 kJmol-1 and a ΔS value of 42.12 Jmol-1 K-1
at 20°C. State whether this reaction will proceed spontaneously at 25°C and explain why. (5 marks)

ΔG = ΔH – TΔS (where ΔH = -10.07 kJ mol-1, ΔS = 42.12 J mol-1 K-1 and T = 293K)
ΔG = 10.96- 2.95 = +8.01 kJ mol-1 (2 s.f.).
Reaction does not proceed as ΔG is positive

[letr]

anyonjeeeeeeeeeeeeeeeeeeeeeeeeee eeeee?

[ms607]

check your value for ΔS - it needs to be in the same units as ΔH (once multiplied with T)

[NightBear]

I'm not quite sure what you did there, I got a negative value for ΔG. Are you sure you've divided ΔS by 1000 to make sure it's in the same units as ΔH?

[ms607]

(Original post by NightBear)
I'm not quite sure what you did there, I got a negative value for ΔG. Are you sure you've divided ΔS by 1000 to make sure it's in the same units as ΔH?

I was tryna get him to realise that by himself :P

[NightBear]

(Original post by ms607)
I was tryna get him to realise that by himself :P

Didn't see your post before I posted mine

[Cable]

You've got to convert the enthalpy value to the correct form by multiplying it by a 1000. So kJ mol-1 is converted to J mol-1.
From there, you should be able to work out the correct answer.

[Cable]

(Original post by letr)
[COLOR="#FF0000"]
ΔG = 10.96- 2.95 = +8.01 kJ mol-1 (2 s.f.).

I believe that should be "3 s.f." not "2 s.f."

[Cable]

I'm not quite sure what you did there, I got a negative value for ΔG. Are you sure you've divided ΔS by 1000 to make sure it's in the same units as ΔH?

Or you could do it this way or my way. Either way, you should get the right answer after your calculations.

[wibletg]

(Original post by letr)
7. The reaction to produce a drug has a ΔH value of –10.07 kJmol-1 and a ΔS value of 42.12 Jmol-1 K-1
at 20°C. State whether this reaction will proceed spontaneously at 25°C and explain why. (5 marks)

ΔG = ΔH – TΔS (where ΔH = -10.07 kJ mol-1, ΔS = 42.12 J mol-1 K-1 and T = 293K)
ΔG = 10.96- 2.95 = +8.01 kJ mol-1 (2 s.f.).
Reaction does not proceed as ΔG is positive

25 degrees C = 298K not 293K

[Katieh007]

(Original post by wibletg)
25 degrees C = 298K not 293K

but it states 20 degrees in the question!!p