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C4 Q

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    http://store.aqa.org.uk/qual/gce/pdf...W-QP-JUN11.PDF
    http://store.aqa.org.uk/qual/gce/pdf...W-MS-JUN11.PDF

    Q8b, the final mark.

    I can't seem to get from 1/(1-x) -1 to x/(1-x)

    Can anyone help?
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    (Original post by uxa595)
    http://store.aqa.org.uk/qual/gce/pdf...W-QP-JUN11.PDF
    http://store.aqa.org.uk/qual/gce/pdf...W-MS-JUN11.PDF

    Q8b, the final mark.

    I can't seem to get from 1/(1-x) -1 to x/(1-x)

    Can anyone help?
     \displaystyle \frac1{1-x} - 1 = \frac1{1-x} - \frac{1(1-x)}{1-x} = \frac{1-(1-x)}{1-x} = \frac{x}{1-x}
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    (Original post by uxa595)
    http://store.aqa.org.uk/qual/gce/pdf...W-QP-JUN11.PDF
    http://store.aqa.org.uk/qual/gce/pdf...W-MS-JUN11.PDF

    Q8b, the final mark.

    I can't seem to get from 1/(1-x) -1 to x/(1-x)

    Can anyone help?
    \dfrac{1}{1-x}-1=\dfrac{1-1+x}{1-x}=\dfrac{x}{1-x}
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    (Original post by raheem94)
     \displaystyle \frac1{1-x} - 1 = \frac1{1-x} - \frac{1(1-x)}{1-x} = \frac{1-(1-x)}{1-x} = \frac{x}{1-x}
    Thanks

    I'm surprised i managed 100 UMS on this one. The boundaries seem ridiculously low.
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    (Original post by uxa595)
    Thanks

    I'm surprised i managed 100 UMS on this one. The boundaries seem ridiculously low.
    No problem.

    I don't have much idea about AQA grade boundaries but well done
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    dammit! by the time I figure out how to lay it our clearly it Latex, Raheem swoops in haha.

    I got owned... again.

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Updated: June 13, 2012
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