C3 logs help please!

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  1. Cleoleo's Avatar
    1 13-06-2012  16:03
    • Exalted and Worshipped Member
    • Posts: 916
    C3 logs help please!
    -1/4ln(1/3) how do I get this to equal 1/4ln3 ??
  2. Anythingoo1's Avatar
    2 13-06-2012  16:06
    • Benevolent Member
    • Location: UK
    • Posts: 622
    Re: C3 logs help please!
    -1/4ln(1/3)

    Bring the negative to the power using the log rule to get 1/4ln(1/3)^-1

    (1/3)^-1 = 3

    therefore -1/4ln(1/3) = 1/4ln(3)
  3. notnek's Avatar
    3 13-06-2012  16:07
    • TSR Demigod
    • Location: Bangkok, Thailand
    Re: C3 logs help please!
    (Original post by Cleoleo)
    -1/4ln(1/3) how do I get this to equal 1/4ln3 ??
    \displaystyle -\frac{1}{4} \ln \frac{1}{3} = -\frac{1}{4} \ln 3^{-1} = \frac{1}{4} \ln 3

    Do you understand how I did this?
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