[nazgul60]

When cot(theta)=0, sec(theta)=0, and cosec(theta)=0, does that mean tan(theta)=0, cos(theta)=0, and sin(theta)=0 respectively??

Thanks

[Allofthem]

No it doesn't.

cot(x) = 1/tan(x), if you were correct then 0 = 1/0
sec(x) = 0 implies 1/cos(x) = 0, not possible, similar for cosec.

[Tomcrease]

Try drawing and and you tell me where they = 0

If you think about it this was

for this to equal 0 would need to be infinity. Which can not happen. Same with Cos and Sec.

as but your calculator will say math error since

[nazgul60]

(Original post by Tomcrease)
Try drawing and and you tell me where they = 0

If you think about it this was

for this to equal 0 would need to be infinity. Which can not happen. Same with Cos and Sec.

as but your calculator will say math error since

So when this is the case what will be the angles? For cosec(theta) = 0 , this is when sin(theta) = 0??

[nazgul60]

(Original post by Tomcrease)
Try drawing and and you tell me where they = 0

For sec(theta):Pie/2 , 3pie/2,
For cosec(theta): pie,2Pie