Seemingly simple gas/pressure question

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  1. internet tough guy's Avatar
    • Overlord in Training
    • Posts: 2,509
    Seemingly simple gas/pressure question
    A hand pump of volume 2.0 x 10-4 m3 is used to force air through a valve into a container of volume 8.0 x 10-4 m3 which contains air at an initial pressure of 101kPa. Calculate the pressure of the air in the container after one stroke of the pump, assuming the temperature if unchanged.



    Firstly I assume that this question involves Boyle's law, which is PV = k (where P = pressure, V = volume, k = constant). I found the constant by subbing in the initial pressure and the container's volume to get 80.8. I then subbed in this constant value, and the volume of 8.0 x 10-4 m3 minus 2.0 x 10-4 m3, because I figured that if air is being pumped in, then the container's volume must be reduced as the pumped in air takes up space. However I get pressure as 134kPa, when the answer at the back have it as 126kPa.

    Honestly I'm stuck, and this is supposed to be an easy starter question as well
  2. BJack's Avatar
    • TSR Idol
    • Posts: 7,539
    Re: Seemingly simple gas/pressure question
    Boyle's law is for a constant quantity of gas. You need the full ideal gas equation, which is

    PV = NkT

    where k is the Boltzmann constant. What you're changing is the number of molecules in the container, not it's volume.

    Presumably the hand pump also contains air at an initial pressure of 101kPa, so you can just look at what fraction of the container's original volume is being added to it. That should give you the answer you're looking for.
  3. internet tough guy's Avatar
    • Overlord in Training
    • Posts: 2,509
    Re: Seemingly simple gas/pressure question
    (Original post by BJack)
    Boyle's law is for a constant quantity of gas. You need the full ideal gas equation, which is

    PV = NkT

    where k is the Boltzmann constant. What you're changing is the number of molecules in the container, not it's volume.

    Presumably the hand pump also contains air at an initial pressure of 101kPa, so you can just look at what fraction of the container's original volume is being added to it. That should give you the answer you're looking for.
    Whats 'N' and 'T'? in the equation? T means temperature, right? - how does this come in, because temperature is unchanged throughout
  4. BJack's Avatar
    • TSR Idol
    • Posts: 7,539
    Re: Seemingly simple gas/pressure question
    (Original post by internet tough guy)
    Whats 'N' and 'T'? in the equation? T means temperature, right? - how does this come in, because temperature is unchanged throughout
    N is the number of molecules you have. T is the temperature; and, yes, it's being held constant so you can ignore that factor.
  5. don'tTRIP.'s Avatar
    • Adored and Respected Member
    • Location: London
    • Posts: 591
    Re: Seemingly simple gas/pressure question
    Surely you'd use P1V1 = P2V2?

    (8.0 x 10-4 + 2.0 x 10-4)(101kPa) = (8.0 x 10-4)(P2)

    Rearrange et voila; you have your answer of 126kPa :holmes:
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