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integrationn?

i was doing a past paper question and i got it wrong

because they differentaited 2^x as 2^Xln2

n i dont understand why? can someone explain?

june 2007, c4, question 2

thanks :smile:
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Original post by raman1
i was doing a past paper question and i got it wrong

because they differentaited 2^x as 2^Xln2

n i dont understand why? can someone explain?

june 2007, c4, question 2

thanks :smile:

Rewrite 2x=eln(2x)=exln(2)2^x = e^{\ln(2^x)} = e^{x \ln(2)}. :yep:

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