literally what you had to do was you have to find the 3 values from AP = OP-OA and the other point from PB and find the 3 points and once you did that you find the differences like for example (2,3,4) ( 4,6,8) you can see that it times by x2 and you have to do the similar thing to that question then you can easily get the ratio sorry if my wording is bad
if anyone has done the jan 2012 paper question 5b, i don't understand how you get t to equal 0, pi/2, pi and 3pi/2. please help!
you get cos2t = 0 right> you have to now let 2t = theta get all the value for which cos theta = 0 so draw the graph out (cos graph) then divide all the solutions by 2 to get T Then sub these values back into get the coordinates for x and Y
I hope im answering the right question, did the paper yesterday so kind of know what your on about!
you get cos2t = 0 right> you have to now let 2t = theta get all the value for which cos theta = 0 so draw the graph out (cos graph) then divide all the solutions by 2 to get T Then sub these values back into get the coordinates for x and Y
I hope im answering the right question, did the paper yesterday so kind of know what your on about!
thanks! do you find the other two solutions by using sin2t=0 as well (so you can get all 4 values of t)?
hello grazie how are u can i ask the question on finding position vectors do we need to find the variable like t and then sub into the equation vector?
Yeah, once you've got t (or lambda, mu, whatever), for a given position on a line then you can easily get the position vector from the line equation. However, it doesn't normally work like that. Normally you get t after you're given a position vector. Then you can use that t for other questions that may follow.
Yeah, once you've got t (or lambda, mu, whatever), for a given position on a line then you can easily get the position vector from the line equation. However, it doesn't normally work like that. Normally you get t after you're given a position vector. Then you can use that t for other questions that may follow.
You either already know or can easily work out lambda for each of the points. Lambda is -6, -4, -1 for A, P, B resp. The ratios in lambda are the same as the ratios of segment lengths. So the ratio asked for is 2:3
I feel like im prepared after doing the solomon, elmwood and edexcel but then i feel like im not and im going to open that paper tomorrow and my mind is going to be blank :/
So dont worry im with you on being scared for this!
can anyone please help me with a vector question in the text book? page84 question 12 d... please please please....
i think you dot product the equation of line l with the scalar quantity of line l which equals to 0. You then find lamda which you would sub back into the equation of l to get the position vector of c!
I think my wording is very crappy, if you dont get it let me know i would try and show the working out!