[MSI_10]

See attachment



The last part of it, the 4 marks.

I say it's 52/3. Dependent on what you get on the Q before.

Someone oppose/confirm?

[Brit_Miller]

(Original post by MSI_10)
See attachment



The last part of it, the 4 marks.

I say it's 52/3. Dependent on what you get on the Q before.

Someone oppose/confirm?

I make it 52/3 as well. It looks like you do too: 64/3 - 48/2 + 20 = 52/3

[aznkid66]

Isn't that the area under the shaded region? Shouldn't it be the definite integral of the straight line minus the definite integral of the curve?

[raheem94]

(Original post by Brit_Miller)
I make it 52/3 as well. It looks like you do too: 64/3 - 48/2 + 20 = 52/3

This is the area below the curve not the required area.

(Original post by aznkid66)
Isn't that the area under the shaded region? Shouldn't it be the definite integral of the straight line minus the definite integral of the curve?

Using the area of trapezium formula will be faster

[Snakefingers13]

Isn't it integrating the line from A to B, then taking away the area between the curves given from integrating f(x) - g(x)?


This was posted from The Student Room's iPhone/iPad App

[Brit_Miller]

Oh yeah, sorry.