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C3

3x+1........-..........2........+......4
(x+2)^3........(x+2)^2........(x+2)

I got the answer
(4x+13)(x+1)
(x+2)^3

But the answer in the book has (x+2)^2 as the denominator... Is this a typo?
(edited 11 years ago)
I'm sorry but you need to use LateX, I have no idea what that equation is meant to be...
Reply 2
Avatar for Aurum
Aurum
Original post by fayled
3x+1........-............2........+........4
(x+2)^3........(x+2)^2........(x+2)

I got the answer
(4x+13)(x+1)
(x+2)^3

But the answer has (x+2)^2 as the denominator... Is this a typo?


Yes.
Reply 3
Avatar for fayled
fayled
OP
9
Original post by flown_muse
I'm sorry but you need to use LateX, I have no idea what that equation is meant to be...


Sorry about that, I tried. How do I use lateX?
Reply 4
Avatar for fayled
fayled
OP
9
Original post by Mr M
That question does not give your answer or the answer you say they have provided. Typo?


I meant the answer given in the textbook was squared rather than cubed as I'd got...
I got what you got.
Original post by fayled
I meant the answer given in the textbook was squared rather than cubed as I'd got...


Your answer is correct. Computer fail on my part.
Original post by fayled
Sorry about that, I tried. How do I use lateX?


Here you go:

http://www.thestudentroom.co.uk/wiki/LaTex :yep:

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