Prove the differential of a scalar multiple of a vector field
Maths and statistics discussion, revision, exam and homework help.
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Re: Prove the differential of a scalar multiple of a vector field
What, exactly, is the definition of this "product rule" you wish to use?
[Either you're saying it's "sort of like the product rule, but they are actually different", or the product rule you wish to use is exactly what you need here, in which case you need to prove it]. -
Re: Prove the differential of a scalar multiple of a vector fieldOh, uh, I meant that the product rule is exactly what I think I need. So I'm right in thinking that, but need to prove that it applies here? I don't think I can prove that though.(Original post by DFranklin)
What, exactly, is the definition of this "product rule" you wish to use?
[Either you're saying it's "sort of like the product rule, but they are actually different", or the product rule you wish to use is exactly what you need here, in which case you need to prove it]. -
Re: Prove the differential of a scalar multiple of a vector field
I might have a proof, but I'm not sure if it's valid. I tried writing Phi as an unknown function or x, y and z, and u as a column vector of 3 more unknown 3D functions. Then I expanded Div[(Phi)(u)] using the product rule on each term - so I had a new column vector with two terms in each direction. Is that allowed, since each entry was a function, but not a vector?
Then I rearranged things to show that the result was equivalent to the proof desired, the result being applicable to n-dimensional space since since the operations involved were all independent of number of dimensions.
Does that work? It feels like I'm assuming things I shouldn't.
In any case, just to check, the later formula in the question, is correctly interpreted as stating that the rate of change of fluid density in a given volume is equal to the rate of flow of fluid in or out of the volume, no?Last edited by 99wattr89; 06-07-2012 at 15:09. -
Re: Prove the differential of a scalar multiple of a vector fieldWhy do you have a column vector after you have "worked out" the Div. The Divergence is a scalar.(Original post by 99wattr89)
I might have a proof, but I'm not sure if it's valid. I tried writing Phi as an unknown function or x, y and z, and u as a column vector of 3 more unknown 3D functions. Then I expanded Div[(Phi)(u)] using the product rule on each term - so I had a new column vector with two terms in each direction. Is that allowed, since each entry was a function, but not a vector?
Then I rearranged things to show that the result was equivalent to the proof desired, the result being applicable to n-dimensional space since since the operations involved were all independent of number of dimensions.
Does that work? It feels like I'm assuming things I shouldn't.
In any case, just to check, the later formula in the question, is correctly interpreted as stating that the rate of change of fluid density in a given volume is equal to the rate of flow of fluid in or out of the volume, no?
This is easiest to do with summation convention. Have you seen this before.
Then the first part would be
div(
u)
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Re: Prove the differential of a scalar multiple of a vector fieldBecause I am a very silly person and I put the terms in a column instead of summing. xD(Original post by thebadgeroverlord)
Why do you have a column vector after you have "worked out" the Div. The Divergence is a scalar.
This is easiest to do with summation convention. Have you seen this before.
Then the first part would be
div(
u)
Also, I do know that notation, and I see exactly how the general proof should go now, thank you!

