can someone please explain Work Done=force*distance, in an inclined plane??
It's the same, but the work has to be done in the direction of the motion. So you need to resolve the force into the component in the direction of motion.
It's the same, but the work has to be done in the direction of the motion. So you need to resolve the force into the component in the direction of motion.
If you apply a force f to the block, as shown, what is the work done if u move it 2 m along the ramp (the force is parallel to the distance)? In terms of the algebra shown, that is.
If you apply a force f to the block, as shown, what is the work done if u move it 2 m along the ramp (the force is parallel to the distance)? In terms of the algebra shown, that is.
If you apply a force f to the block, as shown, what is the work done if u move it 2 m along the ramp (the force is parallel to the distance)? In terms of the algebra shown, that is.
The force is the weight of the block. And the distance has to be a component of 2.