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AS Level physics help

can someone please explain Work Done=force*distance, in an inclined plane??
Original post by GrandMasti
can someone please explain Work Done=force*distance, in an inclined plane??


It's the same, but the work has to be done in the direction of the motion. So you need to resolve the force into the component in the direction of motion.
Reply 2
Original post by Chlorophile
It's the same, but the work has to be done in the direction of the motion. So you need to resolve the force into the component in the direction of motion.



If you apply a force f to the block, as shown, what is the work done if u move it 2 m along the ramp (the force is parallel to the distance)? In terms of the algebra shown, that is.
(edited 9 years ago)
Original post by GrandMasti


If you apply a force f to the block, as shown, what is the work done if u move it 2 m along the ramp (the force is parallel to the distance)? In terms of the algebra shown, that is.


The work done by the force f is fx.
Reply 4
Original post by GrandMasti


If you apply a force f to the block, as shown, what is the work done if u move it 2 m along the ramp (the force is parallel to the distance)? In terms of the algebra shown, that is.


The force is the weight of the block. And the distance has to be a component of 2.

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