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Fractional Indices

Find the value of n

1) 1/8 = 8^n

2) (√7)^5 = 7^n

3) 125^-2/3 x (1/5)^2

Need help on these questions
Reply 1
xm=1xm \displaystyle x^{-m} = \frac{1}{x^m} .

xab=xab \displaystyle x^{\frac{a}{b}} = \sqrt[b]{x^a} .
Reply 2
Original post by B_9710
xm=1xm \displaystyle x^{-m} = \frac{1}{x^m} .

xab=xab \displaystyle x^{\frac{a}{b}} = \sqrt[b]{x^a} .


I know those already but thanks anyways..
Reply 3
Original post by kb12345
Find the value of n

1) 1/8 = 8^n

2) (√7)^5 = 7^n

3) 125^-2/3 x (1/5)^2

Need help on these questions


So apply it if you know it...

18=81\frac{1}{8} = 8^{-1}, so n=?n = \cdots ?
Reply 4
Original post by kb12345
I know those already but thanks anyways..


That's all you need for these questions though ..
Original post by Zacken
So apply it if you know it...

18=81\frac{1}{8} = 8^{-1}, so n=?n = \cdots ?


Why did you delete my post in which I gave the solution to the problem?
Reply 6
Original post by HapaxOromenon2
Why did you delete my post in which I gave the solution to the problem?


Precisely because it was a full solution to the problem.

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