The pH of a 0.15 m solution of a week acid ha is 2.82 at 300 Kelvin write an expression for the acid dissociation constant Ka of ha and determine the value of Ka for this acid at 300 Kelvin stating it's units
The pH of a 0.15 m solution of a week acid ha is 2.82 at 300 Kelvin write an expression for the acid dissociation constant Ka of ha and determine the value of Ka for this acid at 300 Kelvin stating it's units
The acid dissociation constant for a weak acid is basically the general one they give you Ka= (H+)(A-)/(HA) this can also be written at (H+)^2/(HA)