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Chemistry acid base calculation

The pH of a 0.15 m solution of a week acid ha is 2.82 at 300 Kelvin write an expression for the acid dissociation constant Ka of ha and determine the value of Ka for this acid at 300 Kelvin stating it's units
Original post by rshah702
The pH of a 0.15 m solution of a week acid ha is 2.82 at 300 Kelvin write an expression for the acid dissociation constant Ka of ha and determine the value of Ka for this acid at 300 Kelvin stating it's units


The acid dissociation constant for a weak acid is basically the general one they give you
Ka= (H+)(A-)/(HA) this can also be written at (H+)^2/(HA)

you can then plug the numbers in to find ka
Reply 2
Original post by cookiemonster15
The acid dissociation constant for a weak acid is basically the general one they give you
Ka= (H+)(A-)/(HA) this can also be written at (H+)^2/(HA)

you can then plug the numbers in to find ka


Thk you

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