I half remembered a similar question but couldn't quite so I looked it up. This might help.
Change of base formula. Logb x = Loga x/Loga b. Pick a new base and the formula says it is equal to the log of the number in the new basedivided by the log of the old base in the new base.
You could change log8a to a fraction in log 2. I think that works out then.
I half remembered a similar question but couldn't quite so I looked it up. This might help.
Change of base formula. Logb x = Loga x/Loga b. Pick a new base and the formula says it is equal to the log of the number in the new basedivided by the log of the old base in the new base.
You could change log8a to a fraction in log 2. I think that works out then.
so do you mean that Logb2 = loga8 - loga2? really stuck sorry
Find a if Log2a – log8a = 2 I have spent hours trying to answer it but still really stuck ?
I'm glad you asked because I still haven't found a way around it haha! I did see the rule mentioned above yesterday but I can't see how to apply it to this question.
You can think about it intuitively or use the formal change of base rule as follows logab=logcalogcb where c is any number you like.
In this case log2a=log82log8a⇒log2a=3log8a which makes sense if you think about it. Plug this result into the equation and it should be straight forward from there.