cl2+ naoh --> naclo3 + nacl +h20. I'm really struggling to do the half equation for this ;(. I know it's a disportionation reaction and i know the oxidation states of everything. It's just i got it wrong ;( PLZ help!
For ionic equations, look at the product which is formed which is Nacl in this case, and form an equation using just the ions involved. Here, it will be the Na and Cl ions.
Na has a 1+ charge, and Cl has a 1- charge so they are aready balanced in terms of charges. So, we just form the equation:
Na+ + Cl- --> NaCl
For example now if the product was MgCl, then you would need 2 Cl ions as the Mg is a 2+ ions and you need to balance the charges:
Mg2+ + 2Cl- --> MgCl
For the half equation, what is the questions asking you to form the half equation for and from what? I'll go through it with you
For ionic equations, look at the product which is formed which is Nacl in this case, and form an equation using just the ions involved. Here, it will be the Na and Cl ions.
Na has a 1+ charge, and Cl has a 1- charge so they are aready balanced in terms of charges. So, we just form the equation:
Na+ + Cl- --> NaCl
For example now if the product was MgCl, then you would need 2 Cl ions as the Mg is a 2+ ions and you need to balance the charges:
Mg2+ + 2Cl- --> MgCl
For the half equation, what is the questions asking you to form the half equation for and from what? I'll go through it with you
cl2+ naoh --> naclo3 + nacl +h20. I'm really struggling to do the half equation for this ;(. I know it's a disportionation reaction and i know the oxidation states of everything. It's just i got it wrong ;( PLZ help!
Do really mean half equation or are you just trying to balance this?
When we're doing simpler half equations, we usually have some oxygen atoms involved don't we?
normally if its a compound we don't split it up in half equations can u split up ionic compound only I'm not sure .
cause in MgO +Cu --> Mg + CuO
we say half eq is: mg2+ +2e--> mg
and cu --> cu2+ +2e-
but there there are half equations like mno3- --> mn
we say Mno3- +5e- +6h+ --> mn + 3h20 (we added water and h+ to balance the charge and atoms).
but like i split the compound at the top why can't we do the same and say
mn+5 +e- --> mn, like we did with magnesium I'm really confused on this part cause originally for naclo3 i just try to add that in the half equation but you split it up ? why and how do you know that clo3- forms a ion, why cudnt it not be 3/2o2- + cl-1?? i have this gap in my knowledge and i keep messing things up plz help
You gave chlorate (V) in the original post so I just wrote the half equation for chlorine to that.
how do u know when to split up chlorate? cause some formulae like Mno3- u don't split up,like how do u know what ions are formed is there something i gotta learn ;(
how do u know when to split up chlorate? cause some formulae like Mno3- u don't split up,like how do u know what ions are formed is there something i gotta learn ;(
I do not understand what you have written here. You were the one who provide initial equation. I just broke it down into half equations like you asked.