2015 jan c12 q2
hello,, can someone plz explain part b) ... first I used 1/2 of a) which is 13.22775.. Then (1(11)+13.22775) - ( 1(2) +13.22775) and i got 9.. But in the ms it did 9 + 13.22775.. doesnt the 13,2277 cancel out when subtracting...... thanks
Original post by pondsteps
...
I'm not entirely sure what you're talking about but you need only do this:
Unparseable latex formula:
\displaystyle[br]\begin{equation*}\int_2^{11} 1 - \frac{6}{\sqrt{x^2 - 2}} \, \mathrm{d}x = \int_2^{11} 1\, \mathrm{d}x + \frac{1}{2} \int_2^{11} \frac{12}{\sqrt{x^2 -2 }} \, \mathrm{d}x = [x]_2^{11} + \frac{1}{2} (a) = 9 + \frac{1}{2} (a)\end{equation*}
where (a) is your answer to part (a). What confuses you about this?
Original post by Zacken
I'm not entirely sure what you're talking about but you need only do this:
where (a) is your answer to part (a). What confuses you about this?
Unparseable latex formula:
\displaystyle[br]\begin{equation*}\int_2^{11} 1 - \frac{6}{\sqrt{x^2 - 2}} \, \mathrm{d}x = \int_2^{11} 1\, \mathrm{d}x + \frac{1}{2} \int_2^{11} \frac{12}{\sqrt{x^2 -2 }} \, \mathrm{d}x = [x]_2^{11} + \frac{1}{2} (a) = 9 + \frac{1}{2} (a)\end{equation*}
where (a) is your answer to part (a). What confuses you about this?
oh ok thanks....
Original post by pondsteps
oh ok thanks....
Do you understand?
Original post by Zacken
Do you understand?
yup x
Original post by pondsteps
yup x
Awesome!
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