KC Calculation

Can someone help me with the solution to this problem please?

200.0 g of ethyl ethanoate and 7.0 g of water were refluxed together. At equilibrium, the mixture contained 0.25 mol of ethanoic acid. Calculate Kc for the hydrolysis of ethyl ethanoate.
CH3COOCH2CH3(l) + H2O(l)  CH3COOH(l) + CH3CH2OH(l)Thank you :smile:

Reply 1

username986184

3

Original post by emfrostyy

Can someone help me with the solution to this problem please?

200.0 g of ethyl ethanoate and 7.0 g of water were refluxed together. At equilibrium, the mixture contained 0.25 mol of ethanoic acid. Calculate Kc for the hydrolysis of ethyl ethanoate.
CH3COOCH2CH3(l) + H2O(l)  CH3COOH(l) + CH3CH2OH(l)Thank you :smile:

Sure, I'll help. What gave you done so far?

Original post by emfrostyy

Can someone help me with the solution to this problem please?

200.0 g of ethyl ethanoate and 7.0 g of water were refluxed together. At equilibrium, the mixture contained 0.25 mol of ethanoic acid. Calculate Kc for the hydrolysis of ethyl ethanoate.
CH3COOCH2CH3(l) + H2O(l)  CH3COOH(l) + CH3CH2OH(l)Thank you :smile:

What can't you do?

Work out the moles of all of the components remaining at equilibrium ...

Reply 3

Dinaa

17

I'm not sure if this is correct but what I would do is find the initial moles of Ethyl ethanoate and water by using the n=mass/Mr formula.

Then I can find out the number of moles in equilibrium from Ethyl ethanoate and water and then substitute it in the Kc expression.

I doubt I'm right though :redface:

Reply 4

Dinaa

17

Original post by TeachChemistry

Sure, I'll help. What gave you done so far?

Can you see my previous post? Not sure if it's correct and I'll remove it if it is incorrect. :redface:

Reply 5

Proxenus

21

Original post by emfrostyy

Can someone help me with the solution to this problem please?

200.0 g of ethyl ethanoate and 7.0 g of water were refluxed together. At equilibrium, the mixture contained 0.25 mol of ethanoic acid. Calculate Kc for the hydrolysis of ethyl ethanoate.
CH3COOCH2CH3(l) + H2O(l)  CH3COOH(l) + CH3CH2OH(l)Thank you :smile:

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