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Arithmatic Sequences

The question is,
The 12th term of a arithmetic sequence is 35, The 17th term is four times the 2nd term, find the nth term


i know i have to find A and D using simultaneus equations my 1st one is

A+11d= 35

but i dont know how to write my second one, how do i write the 17th term being four times the 2nd term?
Reply 1
Avatar for Zacken
Zacken
22
Original post by SunDun111
The question is,
The 12th term of a arithmetic sequence is 35, The 17th term is four times the 2nd term, find the nth term


i know i have to find A and D using simultaneus equations my 1st one is

A+11d= 35

but i dont know how to write my second one, how do i write the 17th term being four times the 2nd term?


Well the second term is the first term plus the common difference.

So A + 16d = 2(A + d)
Reply 2
Avatar for SunDun111
SunDun111
OP
11
Original post by Zacken
Well the second term is the first term plus the common difference.

So A + 16d = 2(A + d)


wouldnt it be 4(A+D) because A+D = 2nd term, ?
Reply 3
Avatar for Zacken
Zacken
22
Original post by SunDun111
wouldnt it be 4(A+D) because A+D = 2nd term, ?


Yep, it's just that I'm a bit blind and dumb and can't read properly.
Reply 4
Avatar for SunDun111
SunDun111
OP
11
Original post by Zacken
Yep, it's just that I'm a bit blind and dumb and can't read properly.


its fine man haha cheers for your help!
Reply 5
Avatar for Zacken
Zacken
22
Original post by SunDun111
its fine man haha cheers for your help!


No worries.

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