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If there were 5 powers on the LHS and 2 powers on the RHS then our final amount is 5-2 = 3 powers. So Kc in this case is (mol dm-3)3 = mol3 dm-9
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If there were 2 powers on the LHS and 4 powers on the RHS then our final amount is 2-4 = -2 powers. So Kc in this case is (mol dm-3)-2 = mol-2 dm6
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